0=16t^2+48t+36=

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Solution for 0=16t^2+48t+36= equation: 



0=16t^2+48t+36=

We move all terms to the left:

0-(16t^2+48t+36)=0

We add all the numbers together, and all the variables

-(16t^2+48t+36)=0

We get rid of parentheses

-16t^2-48t-36=0

a = -16; b = -48; c = -36;
Δ = b2-4ac
Δ = -482-4·(-16)·(-36)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{48}{-32}=-1+1/2$

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